What is the total power dissipation capability of two 10 watt 500 ohm resistors connected in parallel?

What is the total power dissipation capability of two 10 watt 500 ohm resistors connected in parallel?

• A. 20 watts
• B. 40 watts
• C. 5 watts
• D. None of the above

Answer: (A)

When two resistors are connected in parallel, the total power dissipation capability is the sum of the individual power ratings of each resistor. In this scenario, both resistors have a power rating of 10 watts. When calculating the total power for resistors in parallel, you simply add their individual power ratings together. Therefore, in this case: 10 watts (first resistor) + 10 watts (second resistor) = 20 watts total power capability. This approach to combining the power capacities holds true as long as the applied voltage does not exceed the limits of each individual resistor, which can still safely handle their specified power ratings when operated under this configuration. Thus, the total power dissipation capability of the two resistors connected in parallel is indeed 20 watts.

When two resistors are connected in parallel, the total power dissipation capability is the sum of the individual power ratings of each resistor. In this scenario, both resistors have a power rating of 10 watts.

When calculating the total power for resistors in parallel, you simply add their individual power ratings together. Therefore, in this case:

10 watts (first resistor) + 10 watts (second resistor) = 20 watts total power capability.

This approach to combining the power capacities holds true as long as the applied voltage does not exceed the limits of each individual resistor, which can still safely handle their specified power ratings when operated under this configuration.

Thus, the total power dissipation capability of the two resistors connected in parallel is indeed 20 watts.