What is the reactance of a 2-henry choke at 3000 Hz?

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Multiple Choice

What is the reactance of a 2-henry choke at 3000 Hz?

Explanation:
To determine the reactance of a choke (inductor) at a specific frequency, you can use the formula for inductive reactance, which is given by: \[ X_L = 2 \pi f L \] where: - \( X_L \) is the inductive reactance in ohms, - \( f \) is the frequency in hertz, and - \( L \) is the inductance in henries. In this case, the inductance \( L \) is 2 henries and the frequency \( f \) is 3000 Hz. Plugging these values into the formula, we calculate: 1. First, calculate \( 2 \pi \): - \( 2 \pi \approx 6.2832 \) 2. Now, multiply this by the frequency \( f \): - \( 6.2832 \times 3000 \approx 18849.6 \) 3. Finally, multiply this result by the inductance \( L \): - \( 18849.6 \times 2 \approx 37699.2 \) This calculation gives us an inductive reactance of approximately 37600 ohms, and further adjustments (

To determine the reactance of a choke (inductor) at a specific frequency, you can use the formula for inductive reactance, which is given by:

[ X_L = 2 \pi f L ]

where:

  • ( X_L ) is the inductive reactance in ohms,

  • ( f ) is the frequency in hertz, and

  • ( L ) is the inductance in henries.

In this case, the inductance ( L ) is 2 henries and the frequency ( f ) is 3000 Hz. Plugging these values into the formula, we calculate:

  1. First, calculate ( 2 \pi ):
  • ( 2 \pi \approx 6.2832 )
  1. Now, multiply this by the frequency ( f ):
  • ( 6.2832 \times 3000 \approx 18849.6 )
  1. Finally, multiply this result by the inductance ( L ):
  • ( 18849.6 \times 2 \approx 37699.2 )

This calculation gives us an inductive reactance of approximately 37600 ohms, and further adjustments (

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