The total power dissipation capability of two 10 watt, 500 ohm resistors connected in series is:

The total power dissipation capability of two 10 watt, 500 ohm resistors connected in series is:

• A. 20 watts
• B. 10 watts
• C. 5 watts
• D. None of the above

Answer: (A)

When two resistors are connected in series, the total power dissipation capability is the sum of the power ratings of each individual resistor. In this scenario, each resistor is rated at 10 watts. Therefore, when these two 10-watt resistors are connected in series, the total power capability is simply calculated by adding their power ratings together. Power ratings in series do not diminish; rather, they combine. As a result, the total power dissipation capability of the two resistors is 10 watts from the first resistor plus 10 watts from the second resistor, equating to a total of 20 watts. This understanding aligns with the principles of electrical engineering related to resistances in series. It's important to note that other arrangements or configurations would yield different results, but for series circuits, the power ratings add up directly.

When two resistors are connected in series, the total power dissipation capability is the sum of the power ratings of each individual resistor. In this scenario, each resistor is rated at 10 watts. Therefore, when these two 10-watt resistors are connected in series, the total power capability is simply calculated by adding their power ratings together.

Power ratings in series do not diminish; rather, they combine. As a result, the total power dissipation capability of the two resistors is 10 watts from the first resistor plus 10 watts from the second resistor, equating to a total of 20 watts.

This understanding aligns with the principles of electrical engineering related to resistances in series. It's important to note that other arrangements or configurations would yield different results, but for series circuits, the power ratings add up directly.