The minimum power dissipation rating of a resistor of 20,000 ohms across a potential of 500 V should be:

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Multiple Choice

The minimum power dissipation rating of a resistor of 20,000 ohms across a potential of 500 V should be:

Explanation:
To determine the minimum power dissipation rating of a resistor, you can use the power formula derived from Ohm's Law. The relevant equation is: \[ P = \frac{V^2}{R} \] where \( P \) is the power in watts, \( V \) is the voltage across the resistor, and \( R \) is the resistance in ohms. In this scenario, the voltage \( V \) is 500 volts and the resistance \( R \) is 20,000 ohms. Substituting these values into the formula gives: \[ P = \frac{(500)^2}{20000} \] Calculating this: 1. Calculate \( (500)^2 \), which is 250,000. 2. Divide 250,000 by 20,000, yielding 12.5 watts. Thus, the minimum power dissipation rating required is 12.5 watts. The selection of 25 watts as the answer does not align with the calculated results based on the formula, indicating that while it is a commonly rated power level for a resistor, it exceeds the actual requirement based on the given voltage and resistance values. The correct answer should reflect that the minimum power dissipation

To determine the minimum power dissipation rating of a resistor, you can use the power formula derived from Ohm's Law. The relevant equation is:

[ P = \frac{V^2}{R} ]

where ( P ) is the power in watts, ( V ) is the voltage across the resistor, and ( R ) is the resistance in ohms.

In this scenario, the voltage ( V ) is 500 volts and the resistance ( R ) is 20,000 ohms. Substituting these values into the formula gives:

[ P = \frac{(500)^2}{20000} ]

Calculating this:

  1. Calculate ( (500)^2 ), which is 250,000.

  2. Divide 250,000 by 20,000, yielding 12.5 watts.

Thus, the minimum power dissipation rating required is 12.5 watts. The selection of 25 watts as the answer does not align with the calculated results based on the formula, indicating that while it is a commonly rated power level for a resistor, it exceeds the actual requirement based on the given voltage and resistance values.

The correct answer should reflect that the minimum power dissipation

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