A transmitter operating on 5000 kHz uses a 1000 kHz crystal with a tempered coefficient of - 4 Hz/MHz/0 degrees centigrade. What is the change in the output frequency of the transmitter if the temperature increases 6 degrees centigrade?

Study for the FCC Element 6 – Radiotelegraph Operator Test. Familiarize yourself with theoretical and practical questions. Boost your readiness for the exam with flashcards, multiple-choice questions, and detailed explanations.

Multiple Choice

A transmitter operating on 5000 kHz uses a 1000 kHz crystal with a tempered coefficient of - 4 Hz/MHz/0 degrees centigrade. What is the change in the output frequency of the transmitter if the temperature increases 6 degrees centigrade?

Explanation:
To determine how the output frequency of the transmitter changes with temperature, one must consider both the crystal frequency and its temperature coefficient. The transmitter is initially set to operate at 5000 kHz, utilizing a crystal that oscillates at 1000 kHz and has a temperature coefficient of -4 Hz/MHz per degree Celsius. The negative temperature coefficient indicates that for every degree Celsius rise in temperature, the effective frequency of the crystal decreases. Since the coefficient is given in terms of MHz, it helps to express everything in the same units. The temperature increase is 6 degrees Celsius. Calculating the total change in frequency involves multiplying the temperature increase by the temperature coefficient: Change in frequency = Temperature increase (degrees) × Temperature coefficient (Hz/MHz/°C) Converting the crystal's frequency to MHz: 1000 kHz = 1 MHz. Now applying the formula: Change in frequency = 6 degrees × (-4 Hz/MHz/°C) = -24 Hz. This means that the frequency of the crystal decreases by 24 Hz. To find the new frequency of the transmitter, we need to subtract this change from the original operating frequency: 5000 kHz - 0.024 kHz =

To determine how the output frequency of the transmitter changes with temperature, one must consider both the crystal frequency and its temperature coefficient. The transmitter is initially set to operate at 5000 kHz, utilizing a crystal that oscillates at 1000 kHz and has a temperature coefficient of -4 Hz/MHz per degree Celsius.

The negative temperature coefficient indicates that for every degree Celsius rise in temperature, the effective frequency of the crystal decreases. Since the coefficient is given in terms of MHz, it helps to express everything in the same units. The temperature increase is 6 degrees Celsius.

Calculating the total change in frequency involves multiplying the temperature increase by the temperature coefficient:

Change in frequency = Temperature increase (degrees) × Temperature coefficient (Hz/MHz/°C)

Converting the crystal's frequency to MHz:

1000 kHz = 1 MHz.

Now applying the formula:

Change in frequency = 6 degrees × (-4 Hz/MHz/°C) = -24 Hz.

This means that the frequency of the crystal decreases by 24 Hz. To find the new frequency of the transmitter, we need to subtract this change from the original operating frequency:

5000 kHz - 0.024 kHz =

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy